3(3x+2)-(2x-8)=7^2+1

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Solution for 3(3x+2)-(2x-8)=7^2+1 equation: 



3(3x+2)-(2x-8)=7^2+1

We move all terms to the left:

3(3x+2)-(2x-8)-(7^2+1)=0

We add all the numbers together, and all the variables

3(3x+2)-(2x-8)-50=0

We multiply parentheses

9x-(2x-8)+6-50=0

We get rid of parentheses

9x-2x+8+6-50=0

We add all the numbers together, and all the variables

7x-36=0

We move all terms containing x to the left, all other terms to the right

7x=36

x=36/7

x=5+1/7

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